Optimal. Leaf size=145 \[ \frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right )}{2 c^3 d}-\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d}+\frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{2 c d}-\frac{a x}{c^2 d}-\frac{b \log \left (1-c^2 x^2\right )}{2 c^3 d}+\frac{b x}{2 c^2 d}-\frac{b x \tanh ^{-1}(c x)}{c^2 d}-\frac{b \tanh ^{-1}(c x)}{2 c^3 d} \]
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Rubi [A] time = 0.183807, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 9, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.45, Rules used = {5930, 5916, 321, 206, 5910, 260, 5918, 2402, 2315} \[ \frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right )}{2 c^3 d}-\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d}+\frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{2 c d}-\frac{a x}{c^2 d}-\frac{b \log \left (1-c^2 x^2\right )}{2 c^3 d}+\frac{b x}{2 c^2 d}-\frac{b x \tanh ^{-1}(c x)}{c^2 d}-\frac{b \tanh ^{-1}(c x)}{2 c^3 d} \]
Antiderivative was successfully verified.
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Rule 5930
Rule 5916
Rule 321
Rule 206
Rule 5910
Rule 260
Rule 5918
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int \frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{d+c d x} \, dx &=-\frac{\int \frac{x \left (a+b \tanh ^{-1}(c x)\right )}{d+c d x} \, dx}{c}+\frac{\int x \left (a+b \tanh ^{-1}(c x)\right ) \, dx}{c d}\\ &=\frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{2 c d}+\frac{\int \frac{a+b \tanh ^{-1}(c x)}{d+c d x} \, dx}{c^2}-\frac{b \int \frac{x^2}{1-c^2 x^2} \, dx}{2 d}-\frac{\int \left (a+b \tanh ^{-1}(c x)\right ) \, dx}{c^2 d}\\ &=-\frac{a x}{c^2 d}+\frac{b x}{2 c^2 d}+\frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{2 c d}-\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{c^3 d}-\frac{b \int \frac{1}{1-c^2 x^2} \, dx}{2 c^2 d}-\frac{b \int \tanh ^{-1}(c x) \, dx}{c^2 d}+\frac{b \int \frac{\log \left (\frac{2}{1+c x}\right )}{1-c^2 x^2} \, dx}{c^2 d}\\ &=-\frac{a x}{c^2 d}+\frac{b x}{2 c^2 d}-\frac{b \tanh ^{-1}(c x)}{2 c^3 d}-\frac{b x \tanh ^{-1}(c x)}{c^2 d}+\frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{2 c d}-\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{c^3 d}+\frac{b \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+c x}\right )}{c^3 d}+\frac{b \int \frac{x}{1-c^2 x^2} \, dx}{c d}\\ &=-\frac{a x}{c^2 d}+\frac{b x}{2 c^2 d}-\frac{b \tanh ^{-1}(c x)}{2 c^3 d}-\frac{b x \tanh ^{-1}(c x)}{c^2 d}+\frac{x^2 \left (a+b \tanh ^{-1}(c x)\right )}{2 c d}-\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{c^3 d}-\frac{b \log \left (1-c^2 x^2\right )}{2 c^3 d}+\frac{b \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{2 c^3 d}\\ \end{align*}
Mathematica [A] time = 0.243741, size = 97, normalized size = 0.67 \[ \frac{b \text{PolyLog}\left (2,-e^{-2 \tanh ^{-1}(c x)}\right )+a c^2 x^2-2 a c x+2 a \log (c x+1)-b \log \left (1-c^2 x^2\right )+b \tanh ^{-1}(c x) \left (c^2 x^2-2 c x-2 \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )-1\right )+b c x}{2 c^3 d} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.045, size = 213, normalized size = 1.5 \begin{align*}{\frac{a{x}^{2}}{2\,cd}}-{\frac{ax}{{c}^{2}d}}+{\frac{a\ln \left ( cx+1 \right ) }{{c}^{3}d}}+{\frac{b{\it Artanh} \left ( cx \right ){x}^{2}}{2\,cd}}-{\frac{bx{\it Artanh} \left ( cx \right ) }{{c}^{2}d}}+{\frac{b{\it Artanh} \left ( cx \right ) \ln \left ( cx+1 \right ) }{{c}^{3}d}}+{\frac{b\ln \left ( cx+1 \right ) }{2\,{c}^{3}d}\ln \left ( -{\frac{cx}{2}}+{\frac{1}{2}} \right ) }-{\frac{b}{2\,{c}^{3}d}\ln \left ( -{\frac{cx}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }-{\frac{b}{2\,{c}^{3}d}{\it dilog} \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }-{\frac{b \left ( \ln \left ( cx+1 \right ) \right ) ^{2}}{4\,{c}^{3}d}}+{\frac{bx}{2\,{c}^{2}d}}+{\frac{b}{2\,{c}^{3}d}}-{\frac{b\ln \left ( cx-1 \right ) }{4\,{c}^{3}d}}-{\frac{3\,b\ln \left ( cx+1 \right ) }{4\,{c}^{3}d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{8} \,{\left (c^{3}{\left (\frac{x^{2}}{c^{4} d} + \frac{\log \left (c^{2} x^{2} - 1\right )}{c^{6} d}\right )} + 8 \, c^{3} \int \frac{x^{3} \log \left (c x + 1\right )}{2 \,{\left (c^{4} d x^{2} - c^{2} d\right )}}\,{d x} - c^{2}{\left (\frac{2 \, x}{c^{4} d} - \frac{\log \left (c x + 1\right )}{c^{5} d} + \frac{\log \left (c x - 1\right )}{c^{5} d}\right )} - 8 \, c^{2} \int \frac{x^{2} \log \left (c x + 1\right )}{2 \,{\left (c^{4} d x^{2} - c^{2} d\right )}}\,{d x} + 8 \, c \int \frac{x \log \left (c x + 1\right )}{2 \,{\left (c^{4} d x^{2} - c^{2} d\right )}}\,{d x} - \frac{2 \,{\left (c^{2} x^{2} - 2 \, c x + 2 \, \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )}{c^{3} d} - \frac{2 \, \log \left (2 \, c^{4} d x^{2} - 2 \, c^{2} d\right )}{c^{3} d} + 8 \, \int \frac{\log \left (c x + 1\right )}{2 \,{\left (c^{4} d x^{2} - c^{2} d\right )}}\,{d x}\right )} b + \frac{1}{2} \, a{\left (\frac{c x^{2} - 2 \, x}{c^{2} d} + \frac{2 \, \log \left (c x + 1\right )}{c^{3} d}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b x^{2} \operatorname{artanh}\left (c x\right ) + a x^{2}}{c d x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a x^{2}}{c x + 1}\, dx + \int \frac{b x^{2} \operatorname{atanh}{\left (c x \right )}}{c x + 1}\, dx}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{artanh}\left (c x\right ) + a\right )} x^{2}}{c d x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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